64=-1664t+4t^2+

Solution for 64=-1664t+4t^2+ equation:

64=-1664t+4t^2+

We move all terms to the left:

64-(-1664t+4t^2+)=0

We get rid of parentheses

-4t^2+1664t+64-=0

We add all the numbers together, and all the variables

-4t^2+1664t=0

a = -4; b = 1664; c = 0;
Δ = b2-4ac
Δ = 16642-4·(-4)·0
Δ = 2768896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2768896}=1664$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1664)-1664}{2*-4}=\frac{-3328}{-8}
=+416
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1664)+1664}{2*-4}=\frac{0}{-8}
=0
$